I want to check if a single char is in a C string. The character is the '|'
used for pipelines in Linux (Actually, I also want to check for '<', '>', '>>', '&').
In Java I can do this:
String.indexOf()
But how can I do this in C, without looping through the whole string (a char* string)?
The strchr() function finds the first occurrence of a character in a string. The character c can be the null character (\0); the ending null character of string is included in the search.
You can use string. indexOf('a') . If the char a is present in string : it returns the the index of the first occurrence of the character in the character sequence represented by this object, or -1 if the character does not occur.
The strchr function returns a pointer to the first occurrence of character c in string or a null pointer if no matching character is found.
yes, %c will print a single char: printf("%c", 'h'); also, putchar / putc will work too.
If you need to search for a character you can use the strchr function, like this:
char* pPosition = strchr(pText, '|');
pPosition will be NULL if the given character has not been found. For example:
puts(strchr("field1|field2", '|'));
Will output: "|field2". Note that strchr will perform a forward search, to search backward you can use the strrchr. Now imagine (just to provide an example) that you have a string like this: "variable:value|condition". You can extract the value field with:
char* pValue = strrchr(strchr(pExpression, '|'), ':') + 1;
If what you want is the index of the character inside the string take a look to this post here on SO. You may need something like IndexOfAny() too, here another post on SO that uses strnspn for this.
Instead if you're looking for a string you can use the strstr function, like this:
char* pPosition = strstr(pText, "text to find");
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