How can I check if a file exists in python? [duplicate]

Question

I am trying to make a python script to make entries in an excel file that will have daily entries. I want to check if a file exists then open it. if the file does not exist then I want to make a new file.

if have used os path exists to see if the file is present

     workbook_status = os.path.exists("/log/"+workbookname+".xlxs")
     if  workbook_status = "True":
     # i want to open the file
     Else:
     #i want to create a new file

Answer 1

I think you just need that

try:
    f = open('myfile.xlxs')
    f.close()
except FileNotFoundError:
    print('File does not exist')

If you want to check with if-else than go for this:

from pathlib import Path

my_file = Path("/path/to/file")
if my_file.is_file():
    # file exists

OR

if os.path.isfile("/{file}.{ext}".format(file=workbookname, ext=xlxs)):

Answer 2

import os
import os.path

PATH='./file.txt'

if os.path.isfile(PATH) and os.access(PATH, os.R_OK):
    print "File exists and is readable/there"
else:
    f = open('myfile.txt')
    f.close()