I have a problem with a Hibernate query that looks as follows:
List persons = getList("FROM creator.models.Person p WHERE p.lastName="+userName);
(the getList(String queryString) method just executes the query using a session factory.)
This is my person class:
@Entity
@Table(name="persons")
public class Person{
@Id
@GeneratedValue(strategy=GenerationType.AUTO)
@Column(name = "id")
private Long id;
@Column(name="first_name", nullable=false, updatable=true)
private String firstName;
@Column(name="last_name", nullable=false, updatable=true)
private String lastName;
/// etc
And this is the table:
CREATE TABLE persons(
id INTEGER NOT NULL AUTO_INCREMENT,
first_name CHAR(50),
last_name CHAR(50),
abbreviation CHAR(4),
PRIMARY KEY (id)
);
Searching for a person with the name TestName, I get an exception with this message:
org.hibernate.exception.SQLGrammarException: Unknown column 'TestName' in 'where clause'
at org.hibernate.exception.internal.SQLExceptionTypeDelegate.convert(SQLExceptionTypeDelegate.java:82)
at org.hibernate.exception.internal.StandardSQLExceptionConverter.convert(StandardSQLExceptionConverter.java:49)
//etc
The query created by Hibernate looks like this:
INFO: HHH000397: Using ASTQueryTranslatorFactory
Hibernate: select person0_.id as id8_, person0_.abbreviation as abbrevia2_8_, person0_.first_name as first3_8_, person0_.last_name as last4_8_ from persons person0_ where person0_.last_name=TestName
Dec 10, 2012 5:14:26 PM org.hibernate.engine.jdbc.spi.SqlExceptionHelper logExceptions
Searching for the id (...WHERE p.id="3") works fine, by the way!
I hope somebody knows what is going wrong because for me the query looks right and I can't find out why the lastName is seen as a column name suddenly.
You need to put userName in quotes:
"FROM creator.models.Person p WHERE p.lastName='"+userName+"'";
Or (which is much better) to use parameters
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