Handle whitespaces in arguments to a bash script

Question

I am having issues handling arguments that contain white spaces in a my bash script.

The script

#!/bin/bash
for i in $*
do
    echo "$i"
done

The call (with 2 arguments)

$ ./script.sh "a b" "c"

The actual output (as if there were 3 arguments)

a
b
c

The expected output (as if there were 2 arguments)

a b
c

Can someone explain how to get the expected output?

Answer 1

Change $* to "$@" on the first line.