Grep a whole whitespace-separated word in bash

Question

Say I have this data:

hi helo tmp#100000 bye
100000 hi bye
hi 100000 bye

And 100000 is in variable: $var I want to grep 100000 only as a whole word, desired output:

100000 hi bye
hi 100000 bye

I have tried everything that ever been answered in StuckOverflow and nothing seem to work: grep "\b$var\b", grep -E "[[:blank:]]$var[[:blank:]]" and many many more. I think the problem, might be in #. The solution needs to work for a case where the variable equal: hi.*bye as a Regex as well.

Please help

Answer 1

Non-regex search using awk:

awk -v var="$var" '
{for (i=1; i<=NF; ++i) if ($i == var) {print; break}}' file

100000 hi bye
hi 100000 bye

Otherwise a shorter awk using custom FS:

awk -F "(^|[[:blank:]])$var([[:blank:]]|$)" 'NF > 1' file