grabing a number six lines below a pattern

Question

I have these lines repeating

                               FINAL RESULTS



    NSTEP       ENERGY          RMS            GMAX         NAME    NUMBER
    1000      -4.7910E+01     2.1328E-01     9.4193E-01     C          62

The FINAL RESULTS indicate a average of those values for a set. The output file combines all 1000 sets. I need to grab the number below energy (-4.7910E+01), all 1000 of them in to another file. I need to set FINAL RESULTS as a pattern because other pattern such as NSTEP, ENERGY, RMS.... are repeated in millions.

I'll be grateful for any help.

Answer 1

Something like this should work for you:

awk '/FINAL RESULTS/{for (i=0; i<5; i++) getline; print $2}' <filename>

Answer 2

OK, I think I see now.

awk 'found==1 { print $2; found=0 } $2=="ENERGY" { found=1 }' inputfile

This will get the number below ENERGY regardless of how many lines there are between it and FINAL RESULTS.