going to specific path in scala using scala.sys.process

Question

I have to go to the path of an application to deploy it, I tried using scala.sys.process and did "cd /home/path/somepath" !

It is throwing an exception, Can anyone guide me how I can go to the directory, I cannot deploy it using absolute path because of the dependency the run file has.

Thanks in advance

Answer 1

Although this question is a couple of years old, it's a good question.

To use scala.sys.process to execute something from a specific working directory, pass the required directory as a parameter to ProcessBuilder, as in this working example:

import scala.sys.process._
val scriptPath = "/home/path/myShellScript.sh"
val command = Seq("/bin/bash","-c",scriptPath)
val proc = Process(command,new java.io.File("."))
var output = Vector.empty[String]
val exitValue = proc ! ProcessLogger (
(out) => if( out.trim.length > 0 )
  output +:= out.trim,
(err) =>
  System.err.printf("e:%s\n",err) // can be quite noisy!
)
printf("exit value: %d\n",exitValue)
printf("output[%s]\n",output.mkString("\n"))

If the goal instead is to insure that the environment of the caller defaults to a specific working directory, that can be accomplished by setting the required working directory before launching the jvm.