GnuPG home directory

Question

The following is the code that I have been trying.

import os
import gnupg
import pdb
pdb.set_trace()
gpg = gnupg.GPG(gnupghome='new')
input_data = gpg.gen_key_input(
    key_type="RSA",key_length=1024,
    passphrase='mounika')
key = gpg.gen_key(input_data)
with open(local.txt,'rb')as f:
    status=gpg.encrypt_file(f)

And the following is the error message being generated.

C:\Python27\python.exe C:/SAAS/encrypt.py
Traceback (most recent call last):
  File "C:/SAAS/encrypt.py", line 4, in <module>
    gpg = gnupg.GPG(gnupghome='new')
  File "C:\Python27\lib\site-packages\gnupg.py", line 755, in __init__
    raise OSError(msg)
OSError: Unable to run gpg - it may not be available.

Process finished with exit code 1

I am fairly new to GnuPG and after doing a bit of research I tried replacing gnupghome with homedir. But this is raising another error that homedir is an unexpected keyword.Can soneone pls help me with this issue. Any help would be appreciated.

Answer 1

You need to install the gpg program and make sure it is in your PATH. Or provide the full path to the gpg binary in your constructor, like

gpg = gnupg.GPG(gnupghome='new', gpgbinary='C:\\path\\to\\GnuPG\\pub\\gpg.exe')

Check also the Deployment Requirements for the python-gnupg package for more info.