In C, how can I copy a string with begin and end indices, so that the string will only be partially copied (from begin index to end index)?
This would be like 'C string copy' strcpy, but with a begin and an end index.
We can use string function strncpy() to copy part strings. Part of the second string is added to the first string. strcpy(destination_string, source_string, n);
Just add your offset to the str1 argument of the strncpy call. For example: strncpy(str2, str1 + 1, 5); will copy five bytes into str2 from str1 starting at index 1.
Just subtract the string address from what strchr returns: char *string = "qwerty"; char *e; int index; e = strchr(string, 'e'); index = (int)(e - string);
C strcpy() The strcpy() function copies the string pointed by source (including the null character) to the destination. The strcpy() function also returns the copied string.
Use strncpy
e.g.
strncpy(dest, src + beginIndex, endIndex - beginIndex); This assumes you've
dest is large enough.endIndex is greater than beginIndex beginIndex is less than strlen(src) endIndex is less than strlen(src) Have you checked strncpy?
char * strncpy ( char * destination, const char * source, size_t num );
You must realize that begin and end actually defines a num of bytes to be copied from one place to another.
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