Getting the base name of a file using <filesystem>

Question

In the case of a path like: "C:/Dir/foo.txt", the base name of the file would be "foo". I used to be able to do it like this:

#include <filesystem>
using namespace std;
using namespace std::tr2::sys;
...
path p("C:/Dir/foo.txt");
auto base = p.basename();    // base will now be "foo"

This worked when I used visual studio 2013. Now in the newer version (2015) it will not compile giving me the error:

Error C2039 'basename': is not a member of 'std::experimental::filesystem::v1::path'

What is the equivalent function, or the way to do what I need in the new compiler?

Answer 1

This now appears to be called stem()

Returns the filename identified by the path stripped of its extension.