I have an Enum class in Python 3.7 defined as such:
# activation functions
def relu(x: float) -> float:
return x * (x > 0)
def sigmoid(x: float) -> float:
return 1 / (1 + math.exp(-x))
class Activation(Enum):
SIGMOID = sigmoid
RELU = relu
def __call__(self, x):
return self.value(x)
@classmethod
def values(cls):
return [function.value for function in cls]
I have tried some approaches from other similar questions online, like list(Activation) and Activation.values() but always get an empty list. Any new ideas?
If you use the aenum1 library you can use its member descriptor:
from aenum import Enum, member
class Activation(Enum):
SIGMOID = member(sigmoid)
RELU = member(relu)
def __call__(self, x):
return self.value(x)
@classmethod
def values(cls):
return [function.value for function in cls]
Which could also be written as:
class Activation(Enum):
@member
def SIGMOID(x: float) -> float:
return 1 / (1 + math.exp(-x))
@member
def RELU(x: float) -> float:
return x * (x > 0)
def __call__(self, x):
return self.value(x)
@classmethod
def values(cls):
return [function.value for function in cls]
1 Disclosure: I am the author of the Python stdlib Enum, the enum34 backport, and the Advanced Enumeration (aenum) library.
There's one way to solve this that wasn't mentioned in the linked post without using functools, staticmethod, or a wrapper function.
The problem using a function definition as the only value of the Enum member, is that the Enum's __init__ and __new__ never get called. Having additional values, the Enum does get initialized as usual.
Proof as follows:
import math
from enum import Enum
def relu(x: float) -> float:
return x * (x > 0)
def sigmoid(x: float) -> float:
return 1 / (1 + math.exp(-x))
class Activation(Enum):
SIGMOID = 1, sigmoid
RELU = 2, relu
def __init__(self, *args):
self.your_func = args[1]
def __call__(self, x):
return self.your_func(x)
@classmethod
def values(cls):
return [member.your_func for member in cls]
print(Activation.SIGMOID(2))
print(Activation.RELU(2))
# 0.8807970779778823
# 2
for one_func in Activation.values():
print(one_func(2))
# 0.8807970779778823
# 2
I don't think this is a bug (as suggested in the comments) because:
However the issue with functions is that they are considered to be method definitions instead of attributes
What the several solutions have in common is encapsulating the function definition during the Enum (class syntax) value declaration.
Because of the above, using a "wrapper function" without staticmethod or functools wouldn't work, because it would never be called. Try substituting the following (neither __init__ not __call__ would be called):
SIGMOID = sigmoid
RELU = relu
def __call__(self, *args, **kwargs):
print("inside")
return self.f(*args, **kwargs)
In conclusion, perhaps the most pythonic approach is wrapping the function definition in a list at declaration, and unwrapping in __init__ at initialization:
import math
from enum import Enum
def relu(x: float) -> float:
return x * (x > 0)
def sigmoid(x: float) -> float:
return 1 / (1 + math.exp(-x))
class Activation(Enum):
SIGMOID = [sigmoid]
RELU = [relu]
def __init__(self, your_func):
self.your_func = your_func[0]
def __call__(self, x):
return self.your_func(x)
@classmethod
def values(cls):
return [member.your_func for member in cls]
print(Activation.SIGMOID(2))
print(Activation.RELU(2))
# 0.8807970779778823
# 2
for one_func in Activation.values():
print(one_func(2))
# 0.8807970779778823
# 2
Which saves calling staticmethod (some consider its use unpythonic outside a class definition). And saves importing and calling functools.partial - it involves unnecessary function call overhead with every member access.
Thus, the above approach might arguably be the most pythonic solution.
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