Get timer ticks in Python

Question

I'm just trying to time a piece of code. The pseudocode looks like:

start = get_ticks() do_long_code() print "It took " + (get_ticks() - start) + " seconds." 

How does this look in Python?

More specifically, how do I get the number of ticks since midnight (or however Python organizes that timing)?

Answer 1

In the time module, there are two timing functions: time and clock. time gives you "wall" time, if this is what you care about.

However, the python docs say that clock should be used for benchmarking. Note that clock behaves different in separate systems:

• on MS Windows, it uses the Win32 function QueryPerformanceCounter(), with "resolution typically better than a microsecond". It has no special meaning, it's just a number (it starts counting the first time you call clock in your process).

     # ms windows     t0= time.clock()     do_something()     t= time.clock() - t0 # t is wall seconds elapsed (floating point) 

• on *nix, clock reports CPU time. Now, this is different, and most probably the value you want, since your program hardly ever is the only process requesting CPU time (even if you have no other processes, the kernel uses CPU time now and then). So, this number, which typically is smaller¹ than the wall time (i.e. time.time() - t0), is more meaningful when benchmarking code:

     # linux     t0= time.clock()     do_something()     t= time.clock() - t0 # t is CPU seconds elapsed (floating point) 

Apart from all that, the timeit module has the Timer class that is supposed to use what's best for benchmarking from the available functionality.

¹ unless threading gets in the way…

² Python ≥3.3: there are time.perf_counter() and time.process_time(). perf_counter is being used by the timeit module.

Answer 2

What you need is time() function from time module:

import time start = time.time() do_long_code() print "it took", time.time() - start, "seconds." 

You can use timeit module for more options though.