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Get object keys with the highest value in Javascript

Imagine an object like this:

var values = {
    "2": 1,
    "53": 2,
    "56": 4,
    "57": 9,
    "61": 2,
    "62": 16,
    "63": 2,
    "398": 24,
    ...
}

My goal is, to find the 10 object keys, which have the highest value. In this case: 398, then 62 and so on (= [398, 62, ...]). I know how I can put this into an array, don't know how to receive the property key though.

Important: I can't change the format because it's a server response.

I tried with a for (key in values) {} loop but have no idea how to move on. This similar question and it's answer couldn't really help me either.

like image 280
sandrooco Avatar asked Mar 15 '26 22:03

sandrooco


2 Answers

As commented before:

  • Create an array of keys: Object.keys(object)
  • Sort this array based on value: sort((a,b)=> object[b] - object[a])
  • Get necessary values: keys.slice(0,n)

var value = {2:1,53:2,56:4,57:9,61:2,62:16,63:2,398:24};

function getKeysWithHighestValue(o, n){
  var keys = Object.keys(o);
  keys.sort(function(a,b){
    return o[b] - o[a];
  })
  console.log(keys);
  return keys.slice(0,n);
}

console.log(getKeysWithHighestValue(value, 4))
like image 93
Rajesh Avatar answered Mar 17 '26 11:03

Rajesh


You could sort by the values property and slice the result.

var values = { 2: 1, 53: 2, 56: 4, 57: 9, 61: 2, 62: 16, 63: 2, 398: 24 },
    result = Object
        .keys(values)
        .sort(function (a, b) { return values[b] - values[a]; })
        .slice(0, 10)
        .map(Number);

console.log(result);
.as-console-wrapper { max-height: 100% !important; top: 0; }
like image 39
Nina Scholz Avatar answered Mar 17 '26 12:03

Nina Scholz



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