I am trying to use the following C code to print out an array that I have passed in. It should output the text in hexadecimal format one on each line and I have no problems opening the file. When I first wrote it, I had no problems with it working I opened the output file and my array was there. I changed the fileOutName parameter and now I can't get it to print out anything I have tried changing it back and to a few other things and nothing seems to work. Also when I debug it seems like pOutfile is a bad pointer, but like I said it still creates the file it just won't write anything in it. Any help would be appreciated. Thanks
printoutput(int output[], char * fileOutName){
int i = 0;
FILE * pOutfile;
pOutfile = fopen( fileOutName, "w" );
while(output[i] != 0){
fprintf( pOutfile, "0x%0.4X\n", output[i] );
i++;
}
}
Always clean up after yourself. You're missing an fclose(pOutfile).
It should output the text in hexadecimal format one on each line ...
This line
fprintf( pOutfile, "0x%0.4X\n", 5 );
always formats the same number - 5. It probably should be
fprintf( pOutfile, "0x%0.4X\n", output[i] );
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