I have a function that is declared like:
template<typename T>
void MyFunction();
And a class:
template<typename T>
class MyClass
{
public:
typedef void (*Function_T)();
Function_T m_Func;
void DoSomething()
{
m_Func = &MyFunction<T>;
}
}
When I use the class, I undefined symbols error on MyFunction<T>.
If I change DoSomething to
void DoSomething()
{
m_Func = &MyFunction<T>;
return;
MyFunction<T>();
}
Everything works, but that looks like a workaround and will probably not work with optimization.
I cannot add
template void MyFunction<T>;
to the class because it says it cannot be in class. Is there any other way I can force instantiation of the function?
Edit:
I was able to write a test that fails, but in g++ it has a different message and actually a compiler error: http://ideone.com/RbMnh
Your code will work with optimization as well. Although, I don't know why simply m_Func = &MyFunction<T> doesn't work. GCC 4.3.4 compiles it fine. Which compiler you're using?
And you can also do this:
void DoSomething()
{
if ( false) MyFunction<T>();
m_Func = &MyFunction<T>;
return;
}
By the way, the function pointer type is incorrectly defined. It should be this:
typedef void (*Function_T)();
// ^^ put this!
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