Extract and rename zip file folder

Question

I would like to extract in python a specific folder from a zip file and then rename it after the original file name.

For example I have a file called test.zip containing several folders and subfolders:

xl/media/image1.png
xl/drawings/stuff.png
stuff/otherstuff.png

I want the content of the media folder extracted to a folder called test: test/image1.png

Answer 1

Use

• the zipfile module, particularly ZipFile.extractall()
• os.path.splitext() to get test1 from the string test1.zip
• tmpfile.mkdtemp() to create a temporary directory
• shutil.move() to move entire directory trees.

For example:

#!/usr/bin/env python
"""Usage:
./extract.py test.zip
"""

from zipfile import ZipFile
import os
import sys
import tempfile
import shutil


ROOT_PATH = 'xl/media/'

zip_name = sys.argv[1]
zip_path = os.path.abspath(zip_name)
extraction_dir = os.path.join(os.getcwd(), os.path.splitext(zip_name)[0])
temp_dir = tempfile.mkdtemp()


with ZipFile(zip_path, 'r') as zip_file:
    # Build a list of only the members below ROOT_PATH
    members = zip_file.namelist()
    members_to_extract = [m for m in members if m.startswith(ROOT_PATH)]
    # Extract only those members to the temp directory
    zip_file.extractall(temp_dir, members_to_extract)
    # Move the extracted ROOT_PATH directory to its final location
    shutil.move(os.path.join(temp_dir, ROOT_PATH), extraction_dir)

# Uncomment if you want to delete the original zip file
# os.remove(zip_path)

print "Sucessfully extracted '%s' to '%s'" % (zip_path, extraction_dir)

Use try..except blocks to deal with the various exceptions that can happen when creating directories, removing files and extracting the zip.