Extending class in JS without constructor or super()

Question

I am learning JS and I am told that if I want to extend a class I need to use a constructor and super(). But when I was experimenting I discovered that I can extend the class without. I tried to find an explanation on the internet but couldn't find one. Can somebody explain to me? Thanks

class Person {
  constructor(name, email, address) {
    this.name = name;
    this.email = email;
    this.adress = address;
  }

}

class Employee extends Person {
  getName() {
    return (
      "Hi!," +
      this.name +
      " who has " +
      this.email +
      " as email and lives in " +
      this.adress
    );
  }
}

const newEmployee = new Employee("Ahmed", "[email protected]", "Beverly Hills");

console.log(newEmployee.getName()); *// Hi!,Ahmed who has [email protected] as email and lives in Beverly Hills*

Answer 1

Super method is used to call parent's constructor. You can use it if you need it (using the logic of your parent class in your derived class), but it's not mandatory. You can create a class without constructor, but it will use a default one

constructor() {}

For the derived class, if you don't specify a constructor, it will use

constructor(...args) {
  super(...args);
}