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Express.JS get url path without any additional parameters

Is there any straightforward way to get URL path segment without any additional data (url parameters, css '#', etc.)

for example:

full URL: http://example.com/panel/list
path segment I want to get: /panel/list

full URL: http://example.com/panel/list?user=joe
path segment I want to get: /panel/list

full URL: http://example.com/panel/list#header
path segment I want to get: /panel/list

And any other combination of data that is not path segment of my URL

like image 387
Jakub Pastuszuk Avatar asked Mar 11 '17 13:03

Jakub Pastuszuk


1 Answers

I think you can use req.baseUrl + req.path.

And for full URL use req.originalUrl.

like image 109
rkm Avatar answered Oct 05 '22 03:10

rkm



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