Export module components in Python

Question

In Julia, it is possible to export a function (or a variable, struct, etc.) of a module, after which it can be called in another script without the namespace (once it has been imported). For example:

# helpers.jl
module helpers

function ordinary_function()
# bla bla bla
end

function exported_function()
# bla bla bla
end

export exported_function()
end

# main.jl
include("helpers.jl")
using .helpers

# we have to call the non-exported function with namespace
helpers.ordinary_function()

# but we can call the exported function without namespace
exported_function()

In Python, is there something I can do within the module, so that when the module is imported, the "exported" components can be called directly?

Answer 1

In Python importing is easier than this:

# module.py
def foo(): pass

# file.py
from module import foo
foo()

# file2.py
from file import foo
foo()

This works with classes too.

---

In Python you can also do something like this:

import module
# You have to call like this:
module.foo()

---

When you import a module, all the functions the module imported are considered part of the module. Using the example below:

# file.py
import module

# file2.py
import file
file.module.foo()
# or...
from file import module
module.foo()
# ...or...
from file.module import foo
foo()

---

Notice that in Python the export is not needed.

Look at the documentation: no export keyword exists in Python.