Display items in a list containing a specific name - flutter

Question

In this list, I want to display out all the items that contains this specific name.

My list items: ['US', 'SG', 'US']

print(list.contains("US"));

Using .contains() returns me a true or false but it doesn’t return me the list of strings that contains that. I want to only extract out the items that has 'US' from the list. In this case, there's 2 of it. Please help!

Answer 1

You can try doing it the following way -

List<String> myList = ['US', 'SG', 'US'];
print(myList.where((item) => item.contains("US")));

You can also display it directly inside a Text widget in the following way -

Text(
   myList.where((item) => item.contains("US")).join(" "),
   //The join function joins the elements of the Iterable into a single string with the separator provided as an argument.
),

Hope this helps!

UPDATE:

To display each of the word separately as a list you can display them inside a Column in the following way -

Column(
  children: myList.map((value) {
    if(value.contains("US")){
      return Text(value,);
    } else {
      return Container();
      //Return an empty Container for non-matching case
    }
  }).toList(),
)

The same thing can be used inside a ListView instead of Column if you want it to be scrollable.