I'm trying to understand how classes work a bit better "under the hood" of python.
If I create a class Foo like so
class Foo:
bar = True
Foo is then directly accessible, such as print(Foo) or print(Foo.bar)
However, if I dynamically create create a class and don't set it to a variable like so
type('Foo',(),{'bar':True})
If done in the interpreter it shows <class '__main__.Foo'>. However, when I try to print Foo it's undefined...NameError: name 'Foo' is not defined
Does this mean that when a class is created the "traditional" way (the first Foo class above), that python automatically sets a variable for the class of the same name? Sort of like this
# I realize this is not valid, just to convey the idea
Foo = class Foo:
bar = True
If so, then why doesn't python also create a variable named Foo set to class Foo when using type() to create it?
let's compare your problem with function statements and lambdas (because they play the same role here), consider this function f :
def f ():
return 1
the above snippet of code is not an expression at all, it is a python statement that creates a function named f returning 1 upon calling it.
let's now do the same thing, but in a different way :
f = lambda : 1
the above snippet of code is a python expression (an assignment) that assigns the symbol f to the lambda expression (which is our function) lambda : 1. if we didn't do the assignment, the lambda expression would be lost, it is the same as writing >>> 1 in the python REPL and then trying after that to reference it.
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