Countdown timer giving me negative numbers

Question

I have made a countdown timer in Python3. I have set the month to 1 and the day set to 10 just as examples. When I run it I get negative numbers because that date has already passed.

So then my question is how can I set the year to be something like 2017 so that instead of getting negative numbers I get something like 392 days.

Countdown Timer

import time
from datetime import datetime

while True:
    Datetime = datetime.now()
    Month = 1 - Datetime.month
    Day = 10 - Datetime.day
    Hour = 24 - Datetime.hour
    Minute = 60 - Datetime.minute
    Second = 60 - Datetime.second

    Month = str(Month) + " " + "Month"
    Day =  str(Day) + " " + "Day"
    Hour = str(Hour) + " " + "Hour"
    Minute = str(Minute) + " " + "Minute"
    Second = str(Second) + " " + "Second"

    print(Month)
    print(Day)
    print(Hour)
    print(Minute)
    print(Second)

    time.sleep(1)

Answer 1

You don't need to calculate by hand. Just use the capabilities of the datetime module. It offers time delta calculations:

import datetime
import time

target_date = datetime.datetime(2017, 1, 11)
timedelta_zero = datetime.timedelta(0)

while True:
    diff = target_date - datetime.datetime.now()
    if diff <= timedelta_zero:
        break
    print(diff)
    time.sleep(1)
print('Takeoff!!!')  

prints:

393 days, 17:09:19.278093
393 days, 17:09:18.276930
393 days, 17:09:17.274710
393 days, 17:09:16.272841
393 days, 17:09:15.270777
393 days, 17:09:14.268744
393 days, 17:09:13.267112

If you don't like the microseconds, just strip them off:

>>> print(str(diff).rsplit('.')[0])
393 days, 17:09:19

You need datetime.timedelta(0) as zero value for your time delta comparison. For testing, set target_date to a date just a few second in the future. There should be no negative dates.