I am experimenting with some tuples, and I find myself in the weird position of asking this: how can I copy two tuples that differ in their sizes? Of course, this is intended limited to the minimum length of the two tuples.
So, for instance, let's create three tuples:
std::tuple<int, char, float> a(-1, 'A', 3.14);
std::tuple<int, char, double> b = a;
std::tuple<long, int, double, char> c;
Now, a and b differ in types, and the assignment work (obviously). As for a and c the things get a little more confusing.
My first implementation failed, since I don't know how to recurse on variadic templates with a specific type, so something like this won't work:
template <class T, class U>
void cp(std::tuple<T> from, std::tuple<U> to)
{
}
template <class T, class... ArgsFrom, class U, class... ArgsTo>
void cp(std::tuple<T, ArgsFrom...> from, std::tuple<U, ArgsTo...> to)
{
std::get<0>(to) = std::get<0>(from);
// And how to generate the rest of the tuples?
}
That function won't do anything. So I've devised a second failing attempt, using not the types, but the sizes:
template<class From, class To, std::size_t i>
void copy_tuple_implementation(From &from, To &to)
{
std::get<i>(to) = std::get<i>(from);
copy_tuple_implementation<From, To, i - 1>(from, to);
}
template<>
void copy_tuple_implementation<class From, class To, 0>(From &from, To &to)
{
}
template<class From, class To>
void copy_tuple(From &from, To &to)
{
constexpr std::size_t from_len = std::tuple_size<From>::value;
constexpr std::size_t to_len = std::tuple_size<To>::value;
copy_tuple_implementation<From, To, from_len < to_len ? from_len - 1 : to_len - 1>(from, to);
}
But that won't compile. I have too many errors to display here, but the most significant ones are:
Static_assert failed "tuple_element index out of range"
No type named 'type' in 'std::__1::tuple_element<18446744073709551612, std::__1::__tuple_types<> >'
Read-only variable is not assignable
No viable conversion from 'const base' (aka 'const __tuple_impl<typename __make_tuple_indices<sizeof...(_Tp)>::type, int, int, double>') to 'const __tuple_leaf<18446744073709551615UL, type>'
The interesting part is the index out of range, and the fact that I cannot copy an element with std::get<>.
Can anyone help me in this?
Thanks!
Here's one possibility, using C++14's ready-made integer sequence template (but this is easily reproduced manually if your library doesn't include it):
#include <tuple>
#include <utility>
template <std::size_t ...I, typename T1, typename T2>
void copy_tuple_impl(T1 const & from, T2 & to, std::index_sequence<I...>)
{
int dummy[] = { (std::get<I>(to) = std::get<I>(from), 0)... };
static_cast<void>(dummy);
}
template <typename T1, typename T2>
void copy_tuple(T1 const & from, T2 & to)
{
copy_tuple_impl(
from, to,
std::make_index_sequence<std::tuple_size<T1>::value>());
}
Example:
#include <iostream>
int main()
{
std::tuple<int, char> from { 1, 'x' };
std::tuple<int, char, bool> to;
copy_tuple(from, to);
std::cout << "to<0> = " << std::get<0>(to) << "\n";
}
Another option is to use operator overloading to simulate partial-specialization of your function:
template <std::size_t N>
struct size_t_t {};
template<class From, class To, std::size_t i>
void copy_tuple_implementation(From &from, To &to, size_t_t<i>)
{
std::get<i>(to) = std::get<i>(from);
copy_tuple_implementation(from, to, size_t_t<i-1>{});
}
template<class From, class To>
void copy_tuple_implementation(From &from, To &to, size_t_t<0>)
{
std::get<0>(to) = std::get<0>(from);
}
Or you could just use a helper class:
template<class From, class To, std::size_t i>
struct CopyTuple
{
static void run(From &from, To &to)
{
std::get<i>(to) = std::get<i>(from);
CopyTuple<From,To,i-1>::run(from, to);
}
};
template<class From, class To>
struct CopyTuple<From,To,0>
{
static void run(From &from, To &to)
{
std::get<0>(to) = std::get<0>(from);
}
};
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