Converting Map[String, Double] to java.util.Map[String, java.lang.Double]

Question

I thought we can rely on implicit conversion which converts scala.Double to java.lang.Double. So I tried the following:

import scala.collection.JavaConverters._

object Main extends App {
  def main(args: Array[String]) = {
    val m = Map("10" -> 20.0)
    doSome(m.asJava) //error. Type mismatch found: java.util.Map[String,scala.Double]
                     //                  required: java.util.Map[String,java.lang.Double]
    doSome2(m.asJava)
  }
  def doSome(m: java.util.Map[java.lang.String, java.lang.Double]) = println(m)
  def doSome2(m: java.util.Map[java.lang.String, Double]) = println(m)
}

Why doesn't it work? What would be the idiomatic way to perform such a conversion?

Answer 1

You need the boxed version of double:

import scala.collection.JavaConverters._

m.mapValues(Double.box).asJava

The implicits are able to convert a value of Double to java.lang.Double, but not a Map[String,Double] to java.util.Map[String,java.lang.Double].

String requires no conversion because String is a java.lang.String while Double is a double (primitive).

Answer 2

It seems that for String, you don't need to do any conversion, but is not the case for Double. You can use the method double2Double which is defined in Predef to convert to java.double.

import scala.collection.JavaConverters._

m.map { case (k, v) => k -> double2Double(v) }.asJava

or another way is to do asInstanceOf to convert it to Java map directly.