Convert long filename to short filename (8.3)

Question

I want to convert long filenames/path to short filenames (8.3). I'm developing a script that calls a command line tool that only accepts short filenames.

So i need to convert

C:\Ruby193\bin\test\New Text Document.txt

to

C:\Ruby193\bin\test\NEWTEX~1.TXT

So far i found How to get long filename from ARGV which uses WIN32API to convert short to long filenames (the opposite of what I want to achieve).

Is there any way to get the short filename in Ruby?

Answer 1

You can do this using FFI; there's actually an example that covers your exact scenario in their wiki under the heading "Convert a path to 8.3 style pathname":

require 'ffi'

module Win
  extend FFI::Library
  ffi_lib 'kernel32'
  ffi_convention :stdcall

  attach_function :path_to_8_3, :GetShortPathNameA, [:pointer, :pointer, :uint], :uint
end
out = FFI::MemoryPointer.new 256 # bytes
Win.path_to_8_3("c:\\program files", out, out.length)
p out.get_string # be careful, the path/file you convert to 8.3 must exist or this will be empty

Answer 2

This ruby code uses getShortPathName and don't need additional modules to be installed.

def get_short_win32_filename(long_name)
    require 'win32api'
    win_func = Win32API.new("kernel32","GetShortPathName","PPL"," L")
    buf = 0.chr * 256
    buf[0..long_name.length-1] = long_name
    win_func.call(long_name, buf, buf.length)
    return buf.split(0.chr).first
end