I'm having trouble understanding the concept of using constructors with subclasses.
Here is the parent class:
public class A
{
public A()
{
System.out.println("The default constructor of A is invoked");
}
}
The child class:
public class B extends A
{
public B(String s)
{
System.out.println(s);
}
}
And my main method:
public class C
{
public static void main (String[] args)
{
B b = new B("The constructor of B is invoked");
}
}
When I run C, the output I get is
The default constructor of A is invoked
The constructor of B is invoked
What I don't understand is why the message from class A is getting output. Because you pass in a string argument to the constructor of the B class, shouldn't it just print out s? In other words, shouldn't the output simply be:
The constructor of B is invoked
Thanks in advance, I really appreciate any help you guys can give.
From the docs
If a constructor does not explicitly invoke a superclass constructor, the Java compiler automatically inserts a call to the no-argument constructor of the superclass. If the super class does not have a no-argument constructor, you will get a compile-time error. Object does have such a constructor, so if Object is the only superclass, there is no problem.
So even though you've not explicitly called the super class constructor, the compiler inserts a statement called super() in the constructor of class B.
This is how the class B constructor would look post compilation.
public B(String s){
super(); // this is inserted by the compiler, if you hadn't done it yourself.
System.out.println(s);
}
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