Computed Includes in C

Question

I was reading the C Preprocessor guide page on gnu.org on computed includes which has the following explanation:

2.6 Computed Includes

Sometimes it is necessary to select one of several different header files to be included into your program. They might specify configuration parameters to be used on different sorts of operating systems, for instance. You could do this with a series of conditionals,

#if SYSTEM_1
# include "system_1.h"
#elif SYSTEM_2
# include "system_2.h"
#elif SYSTEM_3 …
#endif

That rapidly becomes tedious. Instead, the preprocessor offers the ability to use a macro for the header name. This is called a computed include. Instead of writing a header name as the direct argument of ‘#include’, you simply put a macro name there instead:

#define SYSTEM_H "system_1.h" 
…
#include SYSTEM_H

This doesn't make sense to me. The first code snippet allows for optionality based on which system type you encounter by using branching if elifs. The second seems to have no optionality as a macro is used to define a particular system type and then the macro is placed into the include statement without any code that would imply its definition can be changed. Yet, the text implies these are equivalent and that the second is a shorthand for the first. Can anyone explain how the optionality of the first code snippet exists in the second? I also don't know what code is implied to be contained in the "..." in the second code snippet.

Answer 1

There's some other places in the code or build system that define or don't define the macros that are being tested in the conditionals. What's suggested is that instead of those places defining lots of different SYSTEM_1, SYSTEM_2, etc. macros, they'll just define SYSTEM_H to the value that's desired.

Most likely this won't actually be in an explicit #define, instead of will be in a compiler option, e.g.

gcc -DSYSTEM_H='"system_1.h"' ...

And this will most likely actually come from a setting in a makefile or other configuration file.