When CodeIgniter is inserting a row into a DB, it doesn't encode PHP booleans into a form MySQL needs.
For example:
$new_record = array(
"name" => "Don",
"is_awesome" => true
);
This will enter into MySQL as this:
name (varchar) is_awesome (tinyint)
Don 0
Anyone know a good way to deal with this? I've been writing (is_awesome == true) ? 1 : 0; then setting the array value, but that sucks.
you can't add true or false to a TINYINT in mysql. you should do 1 or 0 like this
$new_record = array(
"name" => "Don",
"is_awesome" => 1 //1 means it's true
);
$query = $this->db->insert('table_name', $new_record);
then just when you fetch it consider 0 as false and 1 as true
Update:
you can create a function called tinyint_decode like this:
public function tinyint_decode($result = array(), $decode_set = array())
{
//$result is what you got from database after selecting
//$decode_set is what you would like to replace 0 and 1 for
//$decode_set can be like array(0=>'active', 1=>'inactive')
//after fetching the array
$result->is_awesome = ($result->is_awesome == 1 ? $decode_set[1] : $decode_set[0]);
return true;// or anything else
}
this way you can interpret 0 and 1 by anything you like whether it's true and false, active and inactive, or anything else just by passing $decode_set array.
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