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Class and macro with same name from different libraries

Tags:

c++

libraries

In my project I am using 2 libraries. One defines a Status macro and the other has a class named Status in a namespace. This results in a conflict when using the class Status in my code:

// first library
namespace Test {
    class Status {};
}

// second library
#define Status int

// my code
int main() {
    Test::Status test;
    return 0;
}

Error:

error: expected unqualified-id before ‘int’
    8 | #define Status int

How can I use both libraries in my project?

like image 255
mltm Avatar asked Jan 25 '26 14:01

mltm


1 Answers

If you do not need to use the Status macro defined by the 2nd library, then you can simply do the following :

#include <second-library.h>
#undef Status
#include <first-library.h>

If you want to be able to use the Status macro defined by the 2nd library, and the macro expands to a type, you can do the following:

#include <second-library.h>
using Status2 = Status;
#undef Status
#include <first-library.h>

And then use it as Status2 instead of Status.

If you want to be able to use the Status macro, but the macro expands to something other than a type, then I am afraid there is no easy solution:

  • You could look at the definition of the macro and rewrite it with a different name, although this might get you into trouble if, in a future version of the library, they change the definition.

  • You might wrap the library with the macro into a library of your own, so that you can define everything you want with names that you choose, though this might be more work than you bargained for.

like image 167
Mike Nakis Avatar answered Jan 27 '26 03:01

Mike Nakis



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