check if year in string is = or bigger than 2017

Question

I have many posts and I want to add some special offer in the ones that I post this year.

offer name - July 20, 2015
offer name - July 20, 2016
offer name - July 20, 2017
...

I'm doing this:

$a = "offer name - July 20, 2000";
if (preg_match('/2017/',$a)) {
    echo 'offer';
}

it is working for 2017, but I want to add offers in posts from 2017 and next years... 18, 19. any ideas?

Answer 1

This variant iterates over the input and filters by year:

<?php
$input = [
  'offer name - July 20, 2015',
  'offer name - July 20, 2016',
  'offer name - July 20, 2017'
];
$output = [];
array_walk($input, function($entry) use (&$output){
  if (   preg_match('| - \w+\s+\d+,\s+(\d+)$|', $entry, $tokens)
      && intval($tokens[1]) >= 2017 ) {
    $output[] = $entry;
  }
});
print_r($output);

This is a somewhat more compact variant:

<?php
$input = [
  'offer name - July 20, 2015',
  'offer name - July 20, 2016',
  'offer name - July 20, 2017'
];
$output = array_filter($input, function($entry){
  return
         preg_match('| - \w+\s+\d+,\s+(\d+)$|', $entry, $tokens)
      && (intval($tokens[1]) >= 2017);
});
print_r($output);

The output obviously is:

Array
(
    [0] => offer name - July 20, 2017
)

Answer 2

you can use something like that

function isYearAllowed($date, array $allowedYears)
{
    try {
        $date = new \DateTime($date);
    } catch (\Exception $e) {
        return false;
    }
    if(in_array($date->format("Y"), $allowedYears)){
        return true;
    }else{
        return false;
    }

}

Example of usage

$allowedYears = ['2017','2016'];
if(isYearAllowed("2016-12-31", $allowedYears)){
    echo "offer";
}else{
    echo "don't offer";
}
exit;

live demo (https://eval.in/835914)