Check for a specific suffix by RegEx and select entire match including suffix

Question

First of all, this is my first question in the community hence please pardon my wrongs Experts! I am learning regex and faced a scenario where I am failing to create answer by myself.

Let's say if there is humongous paragraph, can we first match on the basis of a specific suffix (say '%') and Only then go back and select the desired logic including suffix?

e.g. part of the text is "abcd efghMNP 0.40 % ijkl mnopSNP -3.20 % xyz". Now in this, if you notice - and I got this much - that there is pattern like

/([MS]NP[\s\d\.-%]+)/

I want to replace "MNP 0.40 %" or "SNP -3.20 %" with blank. replacing part seems easy :) But the problem is with all my learning I am not able to select desired ONLY IF there exists a '%' at the end of match.

The sequence of match I wish to reach at is -- if suffix '%' exists, then match the previous pattern, and if successful then select everything including suffix and replace with empty.

Answer 1

There are several expressions that would do so, for instance this one with added constraints:

[A-Z]{3}\s+[-+]?[0-9.]+\s*%

Test

const regex = /[A-Z]{3}\s+[-+]?[0-9.]+\s*%/gm;
const str = `abcd efghMNP 0.40 % ijkl mnopSNP -3.20 % xyz

"MNP 0.40 %" or "SNP -3.20 %"`;
const subst = ``;

// The substituted value will be contained in the result variable
const result = str.replace(regex, subst);

console.log(result);

Demo 1

Or a simplified version would be:

[A-Z]{3}(.*?)%

Demo 2