Calling Lua function from C++ not working with 2 defined functions

Question

I have a Lua script that I wrote and I have two functions inside it:

function CallbackServerStatus ()
    print("Status exec")
end

function CallbackServerInit ()
    print("Server initialized\n")
end

And this is how I am trying to call my Lua function in C++:

printf("LUA | Exec LUA: CallbackServerInit()\n");
luaL_dofile(LuaEngine::state, "loaders/test.lua");
lua_getglobal(LuaEngine::state, "CallbackServerInit");
lua_pcall(LuaEngine::state, 0, 0, 0);

But in the console "Server initialized\n" is no where to be seen. Am I doing something wrong here?? There isn't even an error, and I only see "Server initialized\n" when I remove the CallbackServerStatus() function.

Answer 1

Ok, I found out that there was a non printing character in my script that was causing the script to fail.

Thank you for the answers!

Answer 2

I think you may need to restructure your code too.

void execute(std::string szScript)
{
  int nStatus = 0;

  nStatus = luaL_loadfile(L, szScript.c_str());
  if(nStatus == 0){ nStatus = lua_pcall(L, 0, LUA_MULTRET, 0); }

  error(nStatus);
}

void callFunction(std::string szName)
{
    int nStatus = 0;

    lua_getglobal(L, szName.c_str());
    nStatus = lua_pcall(L, 0, LUA_MULTRET, 0);

    error(nStatus);
}

void error(int nStatus)
{
    if(nStatus != 0)
    {
      std::string szError = lua_tostring(L, -1);
      szError = "LUA:\n" + szError;
      MessageBox(NULL, szError.c_str(), "Error", MB_OK | MB_ICONERROR);
      lua_pop(L, 1);
    }
}

I've wrote this for my application. You can use it too. This way you can observe any kind of error at compiling scripts or calling functions.

execute("C:\test.lua");
callFunction("MyFunc");