I have 3D array as
 A = [[x1 y1 z1]
      [x2 y2 z2]
      [x3 y3 z3]]
I have to find euclidean distance between each points so that I'll get output with only 3 distance between (row0,row1),(row1,row2) and (row0,row2).
I have some code
dist = scipy.spatial.distance.cdist(A,A, 'euclidean')
but it will give distance in matrix form as
dist= [[0  a   b]
       [a  0   c]
       [b  c   0]]
I want results as [a  b  c].
Consider using scipy.spatial.distance.pdist.
You can do like this.
>>> A = np.array([[1, 2, 3], [4, 5, 6], [10, 20, 30]])
>>> scipy.spatial.distance.pdist(A)
array([  5.19615242,  33.67491648,  28.93095228])
But be careful the order of the output distance is (row0,row1),(row0,row2) and (row1,row2).
You can do something like this:
>>> import numpy as np
>>> from itertools import combinations
>>> A = np.array([[1, 2, 3], [4, 5, 6], [10, 20, 30]])
>>> [np.linalg.norm(a-b) for a, b in combinations(A, 2)]
[5.196152422706632, 33.674916480965472, 28.930952282978865]
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