C socket programming - printf does not print anything on the screen

Question

I am new to unix socket programming. I haven't found myself a comfortable book or tutorial and so I am really struggling.

Here is the program code:

#include<stdio.h>
#include<sys/socket.h>
#include<sys/types.h>
#include <netinet/in.h>

int main(){

    printf("one");
    int socketHandle, newSocketHandle, portno;
    struct sockaddr_in serverAddress, clientAddress;


    printf("two");


    portno = 5001;
    bzero((char *) &serverAddress, sizeof(serverAddress));
    serverAddress.sin_family = AF_INET;
    serverAddress.sin_addr.s_addr = INADDR_ANY;
    serverAddress.sin_port = htons(portno);

    printf("three");

    //creating the socket
    socketHandle = socket(AF_INET, SOCK_STREAM, 0);
    if(socketHandle < 0){
        perror("ERROR : Socket not created.");
        return -1;
    }
    printf("Socket created.");





    //binding the socket
    if(bind(socketHandle, (struct sockaddr *) &serverAddress, sizeof(serverAddress)) < 0){
        perror("ERROR : Socket not binded.");
        return -1;
    }
    printf("Socket binded.");

    //make the socket listen
    listen(socketHandle, 5);

    int len = sizeof(clientAddress);
    //accept the connection requests
    newSocketHandle = accept(socketHandle, (struct sockaddr *) &clientAddress, &len);
    if(newSocketHandle < 0){
        perror("ERROR : Connection not accepted.");
    }

    printf("Connection accepted.");
    return 0;
}

(I tried to print one, two, and three for debugging)

But, even the printf("one") in the first line doesn't work. The cursor just keeps blinking (indicating that the program is still in execution). I can't even get a clue of what is going wrong in the above program. Using the bzero() function also throws a warning saying

warning: incompatible implicit declaration of built-in function ‘bzero’ [enabled by default]

I find socket programming difficult as different websites show different code. Also, please suggest any good tutorial on C/C++ socket programming.

Answer 1

Make sure to print a newline in your debug messages for them to show immediately.

Example printf("one\n");

If you really don't want newlines you can instead flush output with fflush(stdout);.