C++: How do you initialize an internal struct's members using an initialization list?

Question

This is really two questions, noted below:

Currently I have some public internal helper structs (strictly used to pass data around as one object), during construction of an instance of the class I attempted to use initialization lists instead of assignment, but the compiler complained about the individual struct members so I added constructors to the structs...but that just seems like I'm headed down the wrong path.

Is there a way to initialize a struct in an initializer list without using a constructor?

Would these helpers be better suited as an external class?

 
    class Foo {

    public:
    //...
        struct Bar {
            double mass;
            std::pair<double, double> gravMod;
            std::pair<double, double> position;
            std::pair<double, double> velocity;
            bool falling;
            Bar() : mass(0.0), gravMod(std::make_pair(0.0, 0.0)), position(std::make_pair(0.0, 0.0)), velocity(std::make_pair(0.0, 0.0)), falling(false) { };
            Bar(double _mass, std::pair<double, double> _gravMod, std::pair<double, double> _position, std::pair<double, double> _velocity, bool _falling) 
             : mass(_mass), gravMod(_gravMod), position(_position), velocity(_velocity), falling(_falling) { }
            Bar(const Bar& other) 
                : mass(other.mass), gravMod(other.gravMod), position(other.position), velocity(other.velocity), falling(other.falling) { }
        };

        struct Baz {
            std::pair<double, double> acceleration;
            std::pair<double, double> force;
            Baz() : acceleration(std::make_pair(0.0, 0.0)), force(std::make_pair(0.0, 0.0)) { }
            Baz(std::pair<double, double> _acceleration, std::pair<double, double> _force) 
                : acceleration(_acceleration), force(_force) { }
            Baz(const Baz& other) : acceleration(other.acceleration), force(other.force) { }
        };

    //...
    protected:
    //...
    private:
        Bar _currBar;
        Bar _prevBar;
        Baz _currBaz;
        Baz _prevBaz;
    };

 

EDIT

Examples and their associated errors:

 
Foo::Foo() : _currBar{0.0, std::make_pair(0.0, 0.0), std::make_pair(0.0, 0.0), std::make_pair(0.0, 0.0), false}, _currBaz{std::make_pair(0.0, 0.0), std::make_pair(0.0, 0.0)} { }
 

_currBar{ throws: expected '('. The first } throws: expected';'.

 
Foo::Foo() : _currBar.mass(0.0), _currBar.gravMod(std::make_pair(0.0, 0.0)), _currBar.position(std::make_pair(0.0, 0.0)), _currBar.velocity(std::make_pair(0.0, 0.0)), _currBar.falling(false) { }
 

The first _currBar. throws: expected '('. All _currBar. afterwards throw Member 'Foo::_currBar' has already been initialized..

Answer 1

In C++03, there is no way to initialize individual fields of a nested struct, nor is there a way to initialize individual fields of a nested array. In C++0x (now C++11, I guess), they've relaxed this restriction and you can initialize nested structs with a syntax like this:

Foo::Foo() : _currBar{fieldOneValue, fieldTwoValue, /* ... */, fieldNValue}, /* ... etc ... */

Adding constructors to your nested structs is a perfectly viable option in the interim as we wait for more compilers to completely support this feature.