c# generics interface solution

Question

I have a interface named Man. In this interface I have the method getList() that returns a list of type T (dependent by class that implements the interface). I have 3 classes that implement Man: small, normal, and big. Every class has the method getList() thart returns a list of small or a list of normal or a list of big.

interface Man<T>{
  List<T>getList();
}

class small : Man<small>{
  List<small> getList(){
    return new List<small>(); 
  }
}

class normal : Man<normal>{
  List<normal> getList(){
    return new List<normal>(); 
  }
}

class big : Man<big>{
  List<big> getList(){
    return new List<big>(); 
  }
}

Now I have the class: Home that contains a parameter bed that's an instance of Man. Bed can be of various types: small, normal, big. How can I declare the type parameter for bed?

class Home{
  Man bed<> // what i must insert between '<' and '>'??
}

Answer 1

You need to make Home generic, as well:

class Home<T> 
{
    Man<T> bed;

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Edit in response to comments:

If you do not know what type of "Man" will exist, another option would be to make your generic class implement a non-generic interface:

public interface IBed { // bed related things here

public class Man<T> : IBed
{
   // Man + Bed related stuff...

class Home
{
     IBed bed; // Use the interface

You can then develop against the shared contract defined by the interface, and allow any type of IBed to be used in the Home.

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On an unrelated side note, I'd recommend using better naming schemes here - the names don't make a lot of sense... Why is a "Man" named "bed"? You might also want to review the standard Capitalization Conventions.