C# call Generic method dynamically [duplicate]

Question

Given the following Interfaces:

interface IEntity
{
    int Id{get;}
} 

interface IPerson : IEntity
{
    string Name{get;} 
    int Age{get;}
}

interface ITeacher : IPerson 
{
    string StaffId{get;}
}

interface IStudent : IPerson 
{
    string StudentId{get;}
    string Courses{get;}
}

interface IRepository
{
    T Get<T>(int id) where T : IEntity
}

I have the following classes in my namespace

public class EntityBase() : IEntity
{
    int Id{get;set;}
}
public class Teacher : EntityBase, ITeacher{}
public class Sudent : EntityBase, IStudent{}

Currently I am implementing this IRepository as follows:

class Repository: IRepository
{
    IDataContext Context{get;set;}

    T Get<T>(int id) where T : EntityBase
    {
        if(typeof(T) == typeof(Teacher))
            return Context.Get<ITeacher>(id);
        if(typeof(T) == typeof(Sudent))
            return Context.Get<ISudent>(id);
        throw new Exception("Unknown Interface " + typeof(T).Name);
    }
}

Is there a betterway of implementing this? Given that our Context has no knowledge of our data types (Teacher, Student), just its interfaces (ITeacher, IStudent).

Can something like this work?

class Repository: IRepository
{
    T Get<T>(int id) where T : EntityBase
    {
        var MyInterface = FindInterface<T>();
        return Context.Get<MyInterface>(id);
    }
}

Answer 1

I think this will do:

class Repository: IRepository
{
    IDataContext Context{get;set;}

    T Get<T>(int id) where T : EntityBase    
    {
        string[] interfaceList = new string[] 
            { "ITeacher", "IStudent"};

        Type interfaceType = null;
        foreach (string s in interfaceList)
        {
            var types = typeof(T).FindInterfaces((x, y) => x.Name == y.ToString(), s);

            if (types.Length > 0)
                interfaceType = types[0];
        }

        if (interfaceType == null)
            throw new Exception("Unknown Interface " + typeof(T).Name);

        MethodInfo method = typeof(Context).GetMethod("Get");
        MethodInfo generic = method.MakeGenericMethod(interfaceType);

        var returnValue = generic.Invoke(Context, new object[] { id });

        return (T)Convert.ChangeType(returnValue, typeof(T));
    }
}

EDIT: As I don't know the name of your namespace, I have used the Name property to filter the interfaces. In real world usage I will suggest that you use FullName just to be sure, like this:

...
string[] interfaceList = new string[] 
                { "MyNamespace.ITeacher", "MyNamespace.IStudent"};
...
var types = typeof(T).FindInterfaces((x, y) => x.FullName == y.ToString(), s);

Answer 2

I think you can accomplish this through reflection by finding the Get method on Context class, and invoking it as a generic call for the caller-supplied type T. I haven't tested this, but the code should look something like this:

T Get<T>(int id) where T : EntityBase
{
    Type context = Context.GetType();

    MethodInfo getMethod = context.GetMethod("Get", BindingFlags.Public);
    MethodInfo genericGet = getMethod.MakeGenericMethod(new [] {typeof(T)});

    return (T)genericGet.Invoke(Context, new object[] { id } );
}