Building/running iOS app from command line

Question

I am trying to build/run my iOS app from command line. To build the app, the command which I give in shell script is as follows:

PROJECT_DIR="/Users/ingenyous/Desktop/splistV11_test_sh_build/code/app/ios"
TARGET_NAME="splistapp2"
TARGET_SDK="iphoneos5.1"
PROJECT_BUILD_DIR="${PROJECT_DIR}/build/Release-iphoneos"
OUTPUT_DIR="/Users/ingenyous/Desktop/ipa"

# compile project
echo Building Project
cd "${PROJECT_DIR}"
xcodebuild -target "${TARGET_NAME}" -sdk "${TARGET_SDK}" -configuration Release

Here I specify the target name and other parameters. Is it possible to give the target properties like product name and other options in this script itself, which can overwrite the properties given actually in the editor target. or be able to create the target itself from shell script and not needing to create targets from Xcode editor.

Answer 1

You can certainly set the product name using xcodebuild:

xcodebuild -target "${TARGET_NAME}" -configuration Release build PRODUCT_NAME=MyProduct

There can be issues with multiple targets, see this existing SO question

You can set any build setting in this way. A full list of build settings is available on Apple's developer site, and you can also check out the man for xcodebuild.