I've defined some signal:
typedef boost::signals2::signal<void (int temp)> SomeSig;
typedef SomeSig::slot_type SomeSigType;
I have some class:
class SomeClass
{
SomeClass()
{
SomeSig.connect(&SomeClass::doMethod);
}
void doMethod(const SomeSig &slot);
};
And got a lot of errors:
error: ‘BOOST_PP_ENUM_SHIFTED_PARAMS_M’ was not declared in this scope
error: ‘T’ was not declared in this scope
error: a function call cannot appear in a constant-expression
error: a function call cannot appear in a constant-expression
error: template argument 1 is invalid
error: ‘BOOST_SIGNALS2_MISC_STATEMENT’ has not been declared
error: expected identifier before ‘~’ token
error: expected ‘)’ before ‘~’ token
error: expected ‘;’ before ‘~’ token
UPD: New code (the same error):
typedef boost::signals2::signal<void (int keyCode)> SigKeyPressed;
typedef SigKeyPressed::slot_type SigKeyPressedType;
class SomeClass
{
SigKeyPressed mSigKeyPressed;
public:
SomeClass() { mSigKeyPressed.connect(&SomeClass::keyPressed); }
void keyPressed(const SigKeyPressedType &slot);
};
Both Pavel and Keith are correct (+1 for both). SomeSig is a type, you cannot call on a type. You must instantiate SomeSig. You also must provide a pointer to the object when using method function pointers. The _1 is a place holder required during a bind indicating that the method function pointer being bound requires a single argument.
typedef boost::signals2::signal<void (int keyCode)> SigKeyPressed;
typedef SigKeyPressed::slot_type SigKeyPressedType;
class SomeClass
{
SigKeyPressed mSigKeyPressed;
public:
SomeClass() { mSigKeyPressed.connect(boost::bind(&SomeClass::keyPressed, this, _1); }
void keyPressed(const SigKeyPressedType &slot);
};
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