Bitwise operations evaluating to long

Question

I've been converting some Java code to C# and ran into a little pickle. All the documentation on MSDN suggests that all bitwise operations return the type that is being operated on. See: http://msdn.microsoft.com/en-us/library/aa691307(v=vs.71).aspx and http://msdn.microsoft.com/en-us/library/aa691377(v=vs.71).aspx but what ever I do my intellisense keeps telling me that you "Cannot implicitly convert type 'long' to 'int'." The following line is the one with the issue and to me, all the literals in there look like they evaluate to int's and all the operated types are either int's or uint's. What am I missing? I don't even declare any long variables in my file and all the variables below are of type int. The casting to uint is to preserve the unsigned bit-shift operator of java (>>>)

int t1 = ((s13 << 96 - 66) | ((uint)s12 >> 66 - 64)) ^ ((s13 << 96 - 93) | ((uint)s12 >> 93 - 64));

Answer 1

When uint is operated with int the result is long. naturally.

int t1 = (int)((((uint)s13 << 96 - 66) | ((uint)s12 >> 66 - 64)) ^ (((uint)s13 << 96 - 93) | ((uint)s12 >> 93 - 64)));

Note: c# compiler is smart and can deal with constants. so (uint)s | 1 is uint because it can determine that statically.