bash script for string compare [duplicate]

Question

Possible Duplicate:
Bash. How compare two strings in “version” format

All,

I need a good algorithm, script to compare "2.0.9" to "2.0.10" 2.0.9 is less than 2.0.10

"2.0.1" is less than "2.0.9" "2.0.9" is less than "2.0.92"

See the picture? this is on the Mac OS 10.6

Answer 1

Take a look at sort -V and ls -v source code.

Also this is a program I wrote before those other programs learned about version sorting.

#!/usr/bin/perl

@S = <>;
print sort byglob @S;


######################################################################
#
# Sorting function which sorts numerically for numerical parts,
# alphabetically otherwise
# 
sub byglob
{
  my($A) = $a;
  my($B) = $b;
  my($c,$d,$e);

  while ($A && $B)
    {
      $A =~ s/^([0-9]+|[^0-9]+)//;
      $c = $1;
      $B =~ s/^([0-9]+|[^0-9]+)//;
      $d = $1;

      if ($c =~ /\d/ && $d =~ /\d/)
        {
          $e = $c <=> $d;
        }
      else
        {
          $e = $c cmp $d;
        }
      return $e if ($e);
    }
  return $a cmp $b;
}