Bash Grep lines between 2 dates in log file

Question

I have a log file that looks like this:

2015-07-07 11:23:33,006 DEBUG : Invoking handleMessage on interceptor org.apache.cxf.interceptor.LoggingInInterceptor@2798240a

name="New Test User"
domicile="A Place"
name="Test User"

2015-07-07 15:00:33,008 DEBUG : Invoking handleMessage on interceptor org.apache.cxf.interceptor.

Now i call my bash script with a paramter like this:

./test.sh -t 2015-07-07,11:00-2015-07-08,20:00.

So my question is: How can i get the text between the two dates in the log file if i use my time range like 2015-07-07 11:00 until 2015-07-08 20:00?

Thanks

Answer 1

sed -n "/2015-07-07 11:23:33/,/2015-07-07 15:00:33/p"

or more general:

sed -n "/$START/,/$END/p"