bash echo executes command instead of printing it

Question

I have simple bash command that I need to put in shell:

 `for f in $(ls); do echo "File -> $f"; done`

What I get is:

-bash: File: command not found

I don't understand why bash is trying to execute echo statement instead of printing it...

Answer 1

The backticks cause the execution. The command inside the backtiks outputs a string, and the backticks execute that string as a command.

Answer 2

You should'nt be really parsing ls for this. Do something like:

for f in *; do echo "File -> $f"; done

For directories:

for i in *; do if [ -d $i ]; then  echo "File -> $i"; fi ; done

or

find . -type d -exec echo '{}' \;