Ajax-returned elements do not trigger in jQuery

Question

In the HTML, a dropdown with the ID="project_pick" will fire a change event, sending the selected value to the getallreports.php file. This works. The PHP file does a MySQL lookup and returns values inside some HTML. This also works, and looks great on the page. Here below is the jQuery/ajax code that sends the selected item to the PHP file:

$('#project_pick').change(function(e) {
    $.ajax({
        type: "POST",
        url: "getallreports.php",
        data: "project_id=" + $(this).val(),
        success:function(data){
            $('#reportstable').html(data);
        }
    });
});

The returned data appears inside the specified div, and includes anchor tags with specific IDs that should allow other JQuery events to happen. Snippet of returned HTML:

<table><tr>
    <td>Report 1</td><td><a href="#" id="change_1">click to change</a></td>
    <td>Report 2</td><td><a href="#" id="change_2">click to change</a></td>
</tr></table>

The jQuery code to trigger on the above click event is:

$('#change_1').click(function() {
    alert('Change Report One was clicked');
});

However, clicking the above anchor tag does nothing. Also, the returned HTML does not even appear in the source -- although it shows on the screen and in firebug.

What am I missing? How can I get that click event to fire?

EDIT:

I've been reminded about the .on('click', etc) event (thanks Michael and Zirkms), but when I attempted to add it to my code the dropdown's .change event stopped firing. Perhaps the below code needs a facelift?

$('#project_pick').on(change(function(e) {
    $.ajax({
        type: "POST",
        url: "getallreports.php",
        data: "project_id=" + $(this).val(),
        success:function(data){
            $('#reportstable').html(data);
        }
    });
});

Answer 1

On the moment of $('#test').click() code execution #test didn't exist in the DOM, so you didn't bind that handler to somewhere.

Use

$(document).on('click', '#test', function() { ... });

instead

Or (better) if you have a particular node where you insert the retrieved html - use some particular selector rather than $(document) like

$('#reportstable').on(...)

does not even appear in the source

In the "view source" browsers usually show the response from the server as it was retrieved on request, without reflecting JS DOM modifications.