Why this code does not compile (Parent is an interface)?
List<? extends Parent> list = ...
Parent p = factory.get(); // returns concrete implementation
list.set(0, p); // fails here: set(int, ? extends Parent) cannot be applied to (int, Parent)
It's doing that for the sake of safety. Imagine if it worked:
List<Child> childList = new ArrayList<Child>();
childList.add(new Child());
List<? extends Parent> parentList = childList;
parentList.set(0, new Parent());
Child child = childList.get(0); // No! It's not a child! Type safety is broken...
The meaning of List<? extends Parent> is "The is a list of some type which extends Parent. We don't know which type - it could be a List<Parent>, a List<Child>, or a List<GrandChild>." That makes it safe to fetch any items out of the List<T> API and convert from T to Parent, but it's not safe to call in to the List<T> API converting from Parent to T... because that conversion may be invalid.
List<? super Parent>
PECS - "Producer - Extends, Consumer - Super". Your List is a consumer of Parent objects.
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