Accidental expression evaluation in ruby

Question

Why this expression evaluating to 13 ?.

I accidentally evaluated this expression (1_2).next instead of (1+2).next which o/p 4 as result.

=> (1_2).next
=> 13

Please let me know how this is, as i m new to Ruby

Answer 1

Ruby allows you to use _ to break up long numbers, for example

123456789 == 123_456_789

but the latter is a little easier to read, so your code is the same as 12.next