Accessing script positional parameters inside a function

Question

Test script:

#!/bin/bash
var=$1
function test {
echo "dollar1 $1"
echo "var $var"
}
test
exit

output

./test.sh d
dollar1
var d

Why isn't $1 populated inside the function, and is there a way to pass $1...$n to all functions without having them defined as a variable separately?

Answer 1

The function has its own arguments. You can pass all arguments to a function using "$@", which expands to all the positional parameters in order:

test "$@"