Accessing a value in a method using *

Question

In a method definition, when * is used in the following manner, what does it mean?

def foo(*)
   ...
end

I understand the following usage:

def foo(*args)
   ...
end

I am not sure how I will access the method params in the former case.

Answer 1

It means "take and discard any number of parameters".

Both definitions are technically the same, but not giving a name to the argument array means you can't access it.