A PostgreSQL query with 'ANY' is not working

Question

SELECT "Ticket_id"  FROM "Tickets"  WHERE "Status" = 1 AND ("Ticket_id" !=  ANY(array[1,2,3])) Limit 6 

And the result is 1,2,3,4,5,6

Answer 1

You want to use ALL, not ANY. From the fine manual:

9.21.3. ANY/SOME (array)

expression operator ANY (array expression) 

[...] The left-hand expression is evaluated and compared to each element of the array using the given operator, which must yield a Boolean result. The result of ANY is "true" if any true result is obtained.

So if we say this:

1 != any(array[1,2]) 

then we'll get true since (1 != 1) or (1 != 2) is true. ANY is essentially an OR operator. For example:

=> select id from (values (1),(2),(3)) as t(id) where id != any(array[1,2]);  id  ----   1   2   3 (3 rows) 

If we look at ALL, we see:

9.21.4. ALL (array)

expression operator ALL (array expression) 

[...] The left-hand expression is evaluated and compared to each element of the array using the given operator, which must yield a Boolean result. The result of ALL is "true" if all comparisons yield true...

so if we say this:

1 != all(array[1,2]) 

then we'll get false since (1 != 1) and (1 != 2) is false and we see that ALL is essentially an AND operator. For example:

=> select id from (values (1),(2),(3)) as t(id) where id != all(array[1,2]);  id  ----   3 (1 row) 

If you want to exclude all values in an array, use ALL:

select "Ticket_id" from "Tickets" where "Status" = 1   and "Ticket_id" != all(array[1,2,3]) limit 6