How to check whether an object has certain method/property?

Question

You could write something like that :

public static bool HasMethod(this object objectToCheck, string methodName)
{
    var type = objectToCheck.GetType();
    return type.GetMethod(methodName) != null;
} 

Edit : you can even do an extension method and use it like this

myObject.HasMethod("SomeMethod");

via Reflection

 var property = object.GetType().GetProperty("YourProperty")
 property.SetValue(object,some_value,null);

Similar is for methods

It is an old question, but I just ran into it. Type.GetMethod(string name) will throw an AmbiguousMatchException if there is more than one method with that name, so we better handle that case

public static bool HasMethod(this object objectToCheck, string methodName)
{
    try
    {
        var type = objectToCheck.GetType();
        return type.GetMethod(methodName) != null;
    }
    catch(AmbiguousMatchException)
    {
        // ambiguous means there is more than one result,
        // which means: a method with that name does exist
        return true;
    }
} 

Wouldn't it be better to not use any dynamic types for this, and let your class implement an interface. Then, you can check at runtime wether an object implements that interface, and thus, has the expected method (or property).

public interface IMyInterface
{
   void Somemethod();
}


IMyInterface x = anyObject as IMyInterface;
if( x != null )
{
   x.Somemethod();
}

I think this is the only correct way.

The thing you're referring to is duck-typing, which is useful in scenarios where you already know that the object has the method, but the compiler cannot check for that. This is useful in COM interop scenarios for instance. (check this article)

If you want to combine duck-typing with reflection for instance, then I think you're missing the goal of duck-typing.